More Convergence & Divergence with sequences

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SUMMARY

The sequence defined by \( a_n = n \sin(1/n) \) converges to 1. While the initial approach using L'Hôpital's rule is valid, a more straightforward method involves substituting \( x = \frac{1}{n} \), transforming the limit into \( \lim_{x \rightarrow 0} \frac{\sin x}{x} = 1 \). This fundamental limit provides a clearer path to the conclusion without the need for L'Hôpital's rule.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with L'Hôpital's rule
  • Knowledge of trigonometric functions and their properties
  • Basic concepts of sequences and convergence
NEXT STEPS
  • Study the application of L'Hôpital's rule in various limit problems
  • Explore fundamental limits in calculus, particularly \( \lim_{x \rightarrow 0} \frac{\sin x}{x} \)
  • Investigate the properties of sequences and series in mathematical analysis
  • Learn about continuous functions and their limits in calculus
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Students of calculus, mathematics educators, and anyone interested in understanding sequences and limits in mathematical analysis.

shamieh
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Determine whether the sequence converges or diverges, if it converges fidn the limit.

$$a_n = n \sin(1/n)$$

so Can I just do this:

$$n * \sin(1/n)$$ is indeterminate form

so i can use lopitals

so:

$$1 * \cos(1/x) = 1 * 1 = 1$$

converges to 1?
 
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shamieh said:
Determine whether the sequence converges or diverges, if it converges fidn the limit.

$$a_n = n \sin(1/n)$$

so Can I just do this:

$$n * \sin(1/n)$$ is indeterminate form

so i can use lopitals

so:

$$1 * \cos(1/x) = 1 * 1 = 1$$

converges to 1?

Your result is correct... however, if You want to use continuous functions, it is better to set $\displaystyle x=\frac{1}{n}$ and the limit becomes $\displaystyle \lim_{x \rightarrow 0} \frac{\sin x}{x}=1$. This is a 'fundamental limit' and the l'Hopital rule shouldn't be used...

Kind regards

$\chi$ $\sigma$
 

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