- #1

coffeeandativ

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## Homework Statement

A kicker is trying to kick a field goal. The uprights are 3.048m off the ground.

a)At what angle must he kick the ball to ensure the ball goes through the uprights if he kicks it at a velocity of 38.4/s (assume the uprights are at the peak of the ball)?

b) how many yards was the field goal (1yard = 0.914m)

## Homework Equations

vix= vicostheta

viy= visintheha

vf=vi+at

max height= vi+1/2at^2

t= 2d divided by acceleration

## The Attempt at a Solution

Using the equations above I found vix and viy to be

vix=38.4costhetha

viy=38.4 sintheta

to find the time I divided vi by acceleration to get 3.91s then I calculated the max heiight to ground and got 225.05m as an answer, then I added 3.048m to this to get a total of 228.10369m

From this point on I'm unsure how to figure out if the ball went thru, how to find the angle, and how to calculate the yards.