More Football Projectile Motion

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SUMMARY

The discussion focuses on calculating the angle required for a kicker to successfully kick a field goal through uprights that are 3.048 meters high, using an initial velocity of 38.4 m/s. The equations of projectile motion are applied, specifically the horizontal and vertical components of velocity, as well as the time of flight and maximum height formulas. The user calculated the time of flight to be 3.91 seconds and the maximum height to be 228.10369 meters, but faced challenges in determining the angle and the distance in yards. The next steps involve further calculations to find the required angle and the distance of the field goal.

PREREQUISITES
  • Understanding of projectile motion equations
  • Familiarity with trigonometric functions (sine and cosine)
  • Basic knowledge of kinematics
  • Ability to convert units (meters to yards)
NEXT STEPS
  • Calculate the angle using the formula for projectile motion: θ = arctan(viy/vix)
  • Determine the horizontal distance traveled using the time of flight and horizontal velocity
  • Convert the distance from meters to yards using the conversion factor (1 yard = 0.914 m)
  • Explore the effects of varying initial velocities on the angle and distance of projectile motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for practical examples of applying kinematic equations in real-world scenarios.

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Homework Statement


A kicker is trying to kick a field goal. The uprights are 3.048m off the ground.
a)At what angle must he kick the ball to ensure the ball goes through the uprights if he kicks it at a velocity of 38.4/s (assume the uprights are at the peak of the ball)?
b) how many yards was the field goal (1yard = 0.914m)

Homework Equations


vix= vicostheta
viy= visintheha
vf=vi+at
max height= vi+1/2at^2
t= 2d divided by acceleration

The Attempt at a Solution


Using the equations above I found vix and viy to be
vix=38.4costhetha
viy=38.4 sintheta
to find the time I divided vi by acceleration to get 3.91s then I calculated the max heiight to ground and got 225.05m as an answer, then I added 3.048m to this to get a total of 228.10369m

From this point on I'm unsure how to figure out if the ball went thru, how to find the angle, and how to calculate the yards.
 
Physics news on Phys.org
You know the height of the uprights, you know the ball trajectory tops at the uprights, so calculate the time a ball takes when free falling from there and the speed at ground.
 

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