Projectile Motion: Football Thrown at Moving Receiver

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SUMMARY

The discussion centers on a physics problem involving projectile motion, where a football is thrown at a receiver moving away from the quarterback. The football is thrown at a speed of 20 m/s at an angle of 30 degrees, while the receiver runs at 12.25 m/s. The calculations reveal that the horizontal component of the football's velocity is 17.32 m/s, and the vertical component is 10 m/s. The time of flight calculated is 2.04 seconds, leading to a horizontal distance of 61 meters, indicating that the receiver will not catch the football as he is only 10 meters away.

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  • Familiarity with trigonometric functions (sine and cosine)
  • Knowledge of kinematic equations
  • Basic concepts of relative motion
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coffeeandativ
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Homework Statement


A football player throws a football at a player who is 10m away. The football is fired at 20m/s at 30degrees above the horizontal. If the receiver is running straight away from the quarterback at
12.25m/s will he catch the football (assuming the ball is caught at the same height as it is thrown from)?


Homework Equations


vix=vcostheta
viy= vsinthetha
range= vi^2(sinthetha)^2 divided by the acceleration
vf=vi+at
delta x= vit+1/2at^2


The Attempt at a Solution


Using the equations I wrote above this is what I managed to solve so far.
vix=17.32ms
viy= 10ms
to find the time I used vf=vi+at and I got 2.04s which I substituted into the delta x equation to get a total of 61m.

I'm not sure if I'm on the right track to solving this problem or not, any help would be great. Thank you!
 
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It's not clear how you've used the equations that you give to find the values that you state. Perhaps you could lay out your calculations in a bit more detail?
 
What is the condition (in terms of the physics) that must apply in order for their to be a catch?

AM
 

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