Projectile Motion of a Football Problem

Click For Summary
SUMMARY

The discussion focuses on calculating the height of a football when it reaches a goal post 30 meters away, kicked at a velocity of 18 meters/sec at a 50-degree angle. The vertical and horizontal components of the velocity were determined to be 13.79 meters/sec and 11 meters/sec, respectively. The time taken for the ball to reach the goal post was calculated as 2.59 seconds. The next step involves applying the SUVAT equations to find the vertical displacement of the ball at that time.

PREREQUISITES
  • Understanding of projectile motion principles
  • Basic trigonometry for resolving velocity components
  • Familiarity with SUVAT equations in kinematics
  • Ability to perform calculations involving time, velocity, and displacement
NEXT STEPS
  • Learn how to apply SUVAT equations to solve for vertical displacement
  • Study the effects of angle and initial velocity on projectile motion
  • Explore graphical representations of projectile motion
  • Investigate real-world applications of projectile motion in sports
USEFUL FOR

Students studying physics, educators teaching kinematics, and sports analysts interested in the mechanics of projectile motion.

Esau Garcia
Messages
1
Reaction score
0

Homework Statement


A football is kicked from the ground toward a 3.2 meter tall goal post 30 meters away. The ball leaves the ground with a velocity of 18 meters/sec at an angle of 50 degrees from the ground. How high off of the ground is the ball when it reaches the goal post? Does the kicker make the field goal? How high above or below the bar is the ball when it arrives at the goal post?

Homework Equations

The Attempt at a Solution


This is my first thread because I'm new so bare with me. I started the problem by drawing a diagram with a vector of 18 meters/sec, the horizontal component and the vertical component. I solved for each component by using basic trig functions. The results are Vy=13.79 meters/sec and Vx=11 meters/sec. From there I used the total displacement of 30 meters divided by the vertical component of 11 meters/sec to get a time of 2.59 seconds. This time would be the moment in which the ball reaches the goalpost (Is that correct?) But I'm just having difficulty answering the questions. Thanks for the help in advance.
 
Physics news on Phys.org
You've got the time at which the ball will be over head the goal post. Now just think about the motion of the ball along the vertical axis and determine how high off the ground it is. You know the inital velocity, time and acceleration.
 
Esau Garcia said:

Homework Equations

Does "SUVAT" ring a bell?
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
23
Views
4K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 2 ·
Replies
2
Views
19K