MHB More Logic statements and arguments

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The discussion focuses on homework questions related to logic statements and truth tables. Q8 is confirmed correct, while Q9 part 1 requires identifying the negation of a universal statement, which translates to an existential statement. Q9 part 2 is also confirmed correct, noting the negation of a conjunction. For Q10, it is clarified that both arguments are correct if the conclusion is true whenever the premises are true. The thread concludes with a solution intended for future reference.
ertagon2
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So once again this is my homework:
View attachment 7706
If you could please check these answers and help me with Q.9 part 1

Q.8 is just checking if both expressions give the same values right ?
Q.9 part 1 I'm in the blind here
Q.9 part 2 seems logical
Q.10 So if i get this right... for the statement/argument to beright the part before $\therefore$ must give me 1 when $\land$ with part after $\therefore$

This is my truth table for Q.10
https://i.imgur.com/wnthwac.jpg
 

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Hi ertagon2,

Q8 is correct.

For Q9 part 1, the negation of a statement $\forall x : (\text{something})$ is $\exists x : \neg(\text{something})$. This means that you should have a statement equivalent to

$$\exists x\in D : \neg((x\le0)\vee(x\ge2))$$

One of the choices is indeed equivalent to that statement : do you see which one ?

Q9 part 2 is correct : the negation of $A\wedge B$ is $\neg A\vee\neg B$.

For Q10, if I'm not mistaken, both arguments are correct. The rule is that the statement after $\therefore$ (the conclusion) must be true whenever all the statements before $\therefore$ (the premises) are true. You need only check the lines in which all the premises are true; the other lines should be ignored.
 
castor28 said:
Hi ertagon2,

Q8 is correct.

For Q9 part 1, the negation of a statement $\forall x : (\text{something})$ is $\exists x : \neg(\text{something})$. This means that you should have a statement equivalent to

$$\exists x\in D : \neg((x\le0)\vee(x\ge2))$$

One of the choices is indeed equivalent to that statement : do you see which one ?

Q9 part 2 is correct : the negation of $A\wedge B$ is $\neg A\vee\neg B$.

For Q10, if I'm not mistaken, both arguments are correct. The rule is that the statement after $\therefore$ (the conclusion) must be true whenever all the statements before $\therefore$ (the premises) are true. You need only check the lines in which all the premises are true; the other lines should be ignored.

Here's the solution for future generations.
View attachment 7710
 

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First trick I learned this one a long time ago and have used it to entertain and amuse young kids. Ask your friend to write down a three-digit number without showing it to you. Then ask him or her to rearrange the digits to form a new three-digit number. After that, write whichever is the larger number above the other number, and then subtract the smaller from the larger, making sure that you don't see any of the numbers. Then ask the young "victim" to tell you any two of the digits of the...

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