More Logic statements and arguments

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SUMMARY

The discussion focuses on logic statements and their negations, specifically addressing homework questions related to logical expressions. For Q.8, the correctness of the expressions is confirmed. In Q.9 part 1, the negation of a universal statement is defined as the existence of a negated condition, represented as $\exists x\in D : \neg((x\le0)\vee(x\ge2))$. Q.9 part 2 correctly identifies the negation of a conjunction as $\neg A\vee\neg B$. Lastly, Q.10 emphasizes that the conclusion following $\therefore$ must hold true if all premises are true, validating both arguments presented.

PREREQUISITES
  • Understanding of logical expressions and quantifiers, specifically universal ($\forall$) and existential ($\exists$) quantifiers.
  • Familiarity with logical operators, including conjunction ($\land$), disjunction ($\vee$), and negation ($\neg$).
  • Ability to construct and interpret truth tables for logical statements.
  • Knowledge of logical argument structure and validity, particularly in relation to conclusions drawn from premises.
NEXT STEPS
  • Study the principles of logical negation in depth, focusing on universal and existential quantifiers.
  • Learn how to construct and analyze truth tables for complex logical expressions.
  • Explore the rules of logical argumentation and validity, particularly the implications of premises on conclusions.
  • Review examples of logical equivalences, such as De Morgan's laws and their applications in logical reasoning.
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Students studying formal logic, educators teaching logic concepts, and anyone seeking to improve their understanding of logical reasoning and argumentation techniques.

ertagon2
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So once again this is my homework:
View attachment 7706
If you could please check these answers and help me with Q.9 part 1

Q.8 is just checking if both expressions give the same values right ?
Q.9 part 1 I'm in the blind here
Q.9 part 2 seems logical
Q.10 So if i get this right... for the statement/argument to beright the part before $\therefore$ must give me 1 when $\land$ with part after $\therefore$

This is my truth table for Q.10
https://i.imgur.com/wnthwac.jpg
 

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Hi ertagon2,

Q8 is correct.

For Q9 part 1, the negation of a statement $\forall x : (\text{something})$ is $\exists x : \neg(\text{something})$. This means that you should have a statement equivalent to

$$\exists x\in D : \neg((x\le0)\vee(x\ge2))$$

One of the choices is indeed equivalent to that statement : do you see which one ?

Q9 part 2 is correct : the negation of $A\wedge B$ is $\neg A\vee\neg B$.

For Q10, if I'm not mistaken, both arguments are correct. The rule is that the statement after $\therefore$ (the conclusion) must be true whenever all the statements before $\therefore$ (the premises) are true. You need only check the lines in which all the premises are true; the other lines should be ignored.
 
castor28 said:
Hi ertagon2,

Q8 is correct.

For Q9 part 1, the negation of a statement $\forall x : (\text{something})$ is $\exists x : \neg(\text{something})$. This means that you should have a statement equivalent to

$$\exists x\in D : \neg((x\le0)\vee(x\ge2))$$

One of the choices is indeed equivalent to that statement : do you see which one ?

Q9 part 2 is correct : the negation of $A\wedge B$ is $\neg A\vee\neg B$.

For Q10, if I'm not mistaken, both arguments are correct. The rule is that the statement after $\therefore$ (the conclusion) must be true whenever all the statements before $\therefore$ (the premises) are true. You need only check the lines in which all the premises are true; the other lines should be ignored.

Here's the solution for future generations.
View attachment 7710
 

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