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When a bullet traveling at 721 m/s strikes a block of wood originally at rest on a frictionless surface, the bullet emerges from the other side of the block of wood traveling at 349 m/s. If the mass of the bullet is 5.38 g and the mass of the block is 744 g, what is the speed of the block after the collision?
I don't know what to do, I tried doing m1v1 + m2v2 = m1v1' + m2v2', and I couldn't get the answer. Any help would be greatly appreciated.
I don't know what to do, I tried doing m1v1 + m2v2 = m1v1' + m2v2', and I couldn't get the answer. Any help would be greatly appreciated.