- #1

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I don't know what to do, I tried doing m1v1 + m2v2 = m1v1' + m2v2', and I couldn't get the answer. Any help would be greatly appreciated.

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- Thread starter macgirl06
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- #1

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I don't know what to do, I tried doing m1v1 + m2v2 = m1v1' + m2v2', and I couldn't get the answer. Any help would be greatly appreciated.

- #2

Doc Al

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But this is "just" a conservation of momentum problem, so that should work. Show exactly what you did. What values did you use?I don't know what to do, I tried doing m1v1 + m2v2 = m1v1' + m2v2', and I couldn't get the answer.

- #3

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(0.0058kg)(721 m/s) - (0.0058kg)(349m/s) \ 0.744 kg

and that didnt work

and thnks for the fast reply

- #4

Doc Al

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That looks perfectly OK to me:I did the following:

(0.0058kg)(721 m/s) - (0.0058kg)(349m/s) \ 0.744 kg

Speed of block = [(0.0058kg)(721 m/s) - (0.0058kg)(349m/s)]/(0.744 kg)

Check your arithmetic; perhaps you made an error there.

- #5

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- #6

Doc Al

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- #7

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I got it, it was just a calculational error. Thanks for the clarification!

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