• Engineering
How to find different resistance out of 5 same and one different resistance in circuit.?
image of resistances are shown here
http://www.pictures.pk/viewer.php?id=rgh1210158811g.JPG [Broken]

in which 5 are same and one is different. how to recognize the different resistance in the circuit through ohm meter

The Attempt at a Solution

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Defennder
Homework Helper
Er, what are the resistances? And you want to find the equivalent resistance between which two points?

we just have to find the different reistance in the circuit....

Hootenanny
Staff Emeritus
Gold Member
I'm sorry, but I really don't understand the question. Could you please post the question verbatim?

just paste the link starting with pictures.pk and see the figure:yuck:

Hootenanny
Staff Emeritus
Gold Member
just paste the link starting with pictures.pk and see the figure:yuck:
I have done, but that only shows the diagram. I have no idea what the question is?!

Borek
Mentor
I think you are given circuit and the ohmeter and you are told that 5 resistances are identical, while 6th is different - and you have to find this 6th just by measuring resistance between any points in the circuit.

I also suppose you are not allowed to cut wires

impaxion: is there a preset limit to number of measurements you can make, or not?

CEL
The circuit is symmetric. If all resistances were equal, the measurement across any of them would show the same result (the resistance in parallel with the rest of the circuit).
Since there is a different resistance, the measurement across it will be different from the other measurements

Redbelly98
Staff Emeritus
Homework Helper
Could you please post the question verbatim?
It might not be in English.

At any rate, I think Borek has provided an accurate phrasing of what is being asked.

Dick
Homework Helper
It might not be in English.

At any rate, I think Borek has provided an accurate phrasing of what is being asked.
Possibly true. It may be too hard for english speakers. I can't figure the problem out and I speak english. But I do agree the problem is pretty clear.

Dick