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Motion along a straight line (Finding acceleration).

  1. Jul 3, 2015 #1
    Figure 2-24 shows a red car and a green car that move toward each other. Figure 2-25 is a graph of their motion, showing the positions xg0 = 270 m and xr0 = -35 m at time t = 0. The green car has a constant speed of -20 m/s and the red car begins from rest. What is the acceleration magnitude of the red car?
    The graph of their motion shows the two cars intersect their position at t = 12 seconds.

    I started out by interpreting the labels and information.
    Xo (g) : 270m
    Xo (r) : -35m
    (Constant) V (g) : -20m/s
    Vo (r) : 0 m/s.
    t = 12 seconds.

    1. I used the formula X = Xo + ( V - Vo/ 2 )t to get the position at which the cars meet.

    X = 270 + (-20/2)12

    X = 150m,

    Then I used the formula X = Xo + Vot + 1/2at^2 to get the acceleration of the red car.

    150 = -35 + 0 (12) + 1/2a(12)^2.

    This yielded a = 1.68 m/s*s


    The answer is supposed to be a= 0.9m/s*s.


    Where did I go wrong? Was my interpretation of the data incorrect? Or just the way I plugged in the data?
     
  2. jcsd
  3. Jul 3, 2015 #2

    SteamKing

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    Can you post the two figures associated with this problem?
     
  4. Jul 5, 2015 #3
    11668050_1142578102425170_817929921_n.jpg
     
  5. Jul 5, 2015 #4

    SteamKing

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    Why? The green car has a constant speed of -20 m/s, according to the problem statement.

    What's the correct formula for finding distance traveled for an object traveling at constant speed?

    This distance X doesn't appear to be correct, just by looking at the graph which shows the motion of the cars versus time.

    I think the second part of your work went wrong because you made the mistakes in the first part, as discussed above.
     
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