- #1

Sarah Sposato

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The graph of their motion shows the two cars intersect their position at t = 12 seconds.

I started out by interpreting the labels and information.

Xo (g) : 270m

Xo (r) : -35m

(Constant) V (g) : -20m/s

Vo (r) : 0 m/s.

t = 12 seconds.

1. I used the formula X = Xo + ( V - Vo/ 2 )t to get the position at which the cars meet.

X = 270 + (-20/2)12

X = 150m,

Then I used the formula X = Xo + Vot + 1/2at^2 to get the acceleration of the red car.

150 = -35 + 0 (12) + 1/2a(12)^2.

This yielded a = 1.68 m/s*sThe answer is supposed to be a= 0.9m/s*s.Where did I go wrong? Was my interpretation of the data incorrect? Or just the way I plugged in the data?