Motion & Forces: Find Block Speed After 3.9s

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A 3.54 kg block is being pulled by a cord with a force of 10.6 N at a 15° angle, while experiencing a coefficient of kinetic friction of 0.08. Participants in the discussion emphasize using Newton's second law to analyze forces in both the x and y directions, clarifying the roles of tension, friction, and normal force. The tension's horizontal and vertical components are identified, and the correct equations for net forces are established. The normal force is not zero, and friction acts opposite to the direction of motion, leading to the conclusion that the block remains on the ground. Ultimately, the discussion highlights the importance of correctly identifying forces to solve for the block's speed after 3.9 seconds.
  • #31
Ahhh...I am getting the wrong answer...
okay I used Vf = Vo + at
Vf = 0 + (2.169 m/s^2)(3.98s) = 8.63 m/s
 
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  • #32
Sorry nevermind I don't know why I used 3.98! I have been doing this stuff all day and there are so many numbers in my head I am getting confused lol!
 

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