Motion in 1D problem, it's not supposed to be this hard.

Click For Summary

Homework Help Overview

The problem involves a truck maintaining a constant speed while approaching a car that accelerates from rest at a traffic light. The goal is to determine how close the truck comes to the car before the car reaches its final speed.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the speeds of the truck and the car, questioning the implications of finding the time when their speeds are equal. There is an exploration of the distance between the two vehicles as the car accelerates.

Discussion Status

Some participants have offered guidance on focusing on the moment when both vehicles have the same velocity, suggesting that this is key to determining the closest distance. Multiple interpretations of the problem are being explored, particularly regarding the conditions under which the truck and car interact.

Contextual Notes

There is mention of the professor not providing examples, which may contribute to the participants' uncertainty in approaching the problem. The discussion reflects a lack of explicit consensus on the best method to find the solution.

Executioner
Messages
4
Reaction score
0

Homework Statement



To save fuel, some truck drivers try to maintain a constant speed when possible. A truck traveling at 91.0 km/hr approaches a car stopped at the red light. When the truck is 115.7 meters from the car the light turns green and the car immediately begins to accelerate at 2.90 m/s^2 to a final speed of 106.0 km/hr. How close does the truck come to the car assuming the truck does not slow down?

Homework Equations



I might be wrong but I've used this formula:
Vo = "V knot"
Xo = "X knot" (initial position)

X = (1/2)at^2 + volt + Xo



The Attempt at a Solution



I convert the trucks velocity from 91 km/hr into 25.278 m/s, and I've converted the car's final velocity to 29.44 m/s. I tried to do the above equation for both vehicles and set them equal to each other so I'll know what time they meet. I was thinking this way and then when I find TIME, I'll plug it in back into one of the "X = (1/2) etc" equation to find the distance.

My professor doesn't show us any examples, all he did was just show us how we get the equation. Thanks guys for any help, I really appreciate it.
 
Physics news on Phys.org
The problem asks the minimal distance the truck approaches the car. If you find a time when they meet it means that the truck and the car will collide. Just think: The truck goes with uniform speed. The car accelerates from zero speed. Its speed increases, reaches that of the truck and gets even higher up to 106 km/h. Up to what speed will the distance decrease between them?

ehild
 
The truck is gaining on the car right up until the cars speed > the trucks speed. At what time does the cars speed equal the trucks speed? Where are the truck and car at this time?
 
Thanks guys, so at some point the car AND the truck both have the same velocity right?
 
Executioner said:
Thanks guys, so at some point the car AND the truck both have the same velocity right?

Yes, and you have to find that moment.

ehild
 
OK, so the car will hit the speed of 25.278 (which is the same like the truck) at some time T right? I find that T and then plug it back into the position equation for each of the vehicles right? After that subtract the two and I get how much farther (closest) they are apart?
 
Awesome! I got it! I knew it had something to do with time when they both has the same velocity! You just confirmed it and helped me out! Thank you so much guys! :)
 
Congratulation! Good job!

ehild
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
15
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
2K