Motion in one dimension of a swimmer

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SUMMARY

The discussion centers on calculating the speed required for a second swimmer to catch up to a leading swimmer in a relay race. The first swimmer has a 0.50-second lead and swims at a constant speed of 4.0 m/s over a distance of 50 meters. To determine the necessary speed for the second swimmer, the formula d = rt is applied, leading to the conclusion that the second swimmer must also swim at a constant speed of 4.0 m/s to reach the end of the pool simultaneously with the leader.

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  • Understanding of basic kinematics, specifically the relationship between distance, speed, and time.
  • Familiarity with the formula d = rt (distance = rate × time).
  • Knowledge of constant speed motion and its implications.
  • Ability to solve algebraic equations for unknown variables.
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  • Explore advanced kinematic equations for varying speeds and accelerations.
  • Learn about relative motion concepts in physics.
  • Study real-world applications of speed calculations in sports and relay races.
  • Investigate the impact of drag and resistance on swimming speeds.
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Students studying physics, coaches analyzing swimmer performance, and anyone interested in the mechanics of motion in sports.

Alice-Shallom
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Hi, i need help with the following:

One swimmer in a relay race has a 0.50-s lead and is swimming at a constant speed of 4.0 m/s. He has 50 m to swim before reaching the end of the pool. A second swimmer moves in the same direction as the leader. What constant speed must the second swimmer have in order to catch up to the leader at the end of the pool?

I understand that since the 1st swimmer swims at constant speed, he has zero accelaration.

Is it useful to use this formula? Speed = Distance / Time
If not, which formula can i use?

Thanks.
 
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Both swimmers swim at constant speeds. And, yes, V = D/T will be very useful.

Ask yourself: How much of a lead (in distance) does the first swimmer have? How long is the pool? How long will it take the first swimmer to reach the end?

Then ask: How fast must the second swimmer swim if he is to get all the way across the pool in the same time that the first swimmer takes to swim 50 m?
 


To find the constant speed that the second swimmer must have in order to catch up to the leader, we can use the formula for distance: d = rt, where d is the distance, r is the rate (or speed), and t is the time. In this case, we know that the distance is 50 m and the time is 0.50 s for the first swimmer. Plugging these values into the formula, we get:

50 m = (4.0 m/s)t

Solving for t, we get t = 12.5 s.

Since the second swimmer needs to catch up to the leader at the end of the pool, their distance and time will be the same. We can set up a similar equation for the second swimmer:

50 m = (rs)t

Where r is the unknown speed of the second swimmer and s is the same time of 12.5 s. Solving for r, we get:

r = 4.0 m/s

Therefore, the second swimmer must also swim at a constant speed of 4.0 m/s in order to catch up to the leader at the end of the pool. This makes sense since both swimmers are covering the same distance in the same amount of time, they must have the same speed in order to reach the end at the same time.

In summary, we can use the formula d = rt to solve for the speed of the second swimmer, since they are both covering the same distance in the same amount of time. I hope this helps!
 

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