(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A swimmer who can swim at a speed of0.80m/sin still water heads directly across a river86mwide. The swimmer lands at a position on the far bank54 mdownstream from the starting point.Determine:

(C) The direction of departure that would have taken the swimmer directly across the river.

(s - swimmer

g - ground

w - water

Vsw = 0.8 m/s

d across stream = 86m)

2. Relevant equations

(n/a - see bellow)

3. The attempt at a solution

From the previous two parts of the question I determined that it took the swimmer107.5sto cross the river and thus the speed of the current is0.5 m/s [E]. And that the velocity of the swimmer relative to the shore was0.94 m/s [58 N of E]. (Which according to my textbook is correct.)

(t=107.5s

Vwg = 0.5 m/s [E]

Vsg=0.94 m/s [58 N of E])

Now, I figured that in order to end up straight across where you start from, you would have to swim[58 N of W]since the current resulted in the swimmer following a path of[58 N of E]. (So this would negate the effect of the current?) However, according to the textbook the answer is[W 51 N]and I have no clue how else to approach this question. Any help/tips please?

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Relative Motion (Swimmer Crossing River Question)

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