Calculating Distance and Displacement in One Dimension

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SUMMARY

The discussion focuses on calculating the total distance and displacement of a car traveling in one dimension. The car moves north at 30 m/s for 30 minutes and then south at 40 m/s for 15 minutes. The correct approach involves converting the speeds to consistent units, calculating the distance for each segment using the formula d = speed x time, and then determining displacement by considering the direction of travel. The key takeaway is that distance is the total path traveled, while displacement is the net change in position.

PREREQUISITES
  • Understanding of kinematic equations, specifically d = speed x time
  • Knowledge of unit conversion between meters per second (m/s) and kilometers per hour (km/h)
  • Familiarity with vector concepts, particularly directionality in one-dimensional motion
  • Basic grasp of the difference between distance and displacement
NEXT STEPS
  • Practice problems involving distance and displacement in one-dimensional motion
  • Learn about unit conversions between different speed measurements
  • Explore vector addition and its application in multi-dimensional motion
  • Study the implications of direction on displacement in various scenarios
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators seeking to clarify concepts of distance and displacement in one-dimensional motion.

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Homework Statement


A car travels north at 30 m/s for one half hour. It then travels south at 40 m/s for 15
minutes. The total distance the car has traveled and its displacement are?




Homework Equations





The Attempt at a Solution


First of all i converted from m/s to km/h. I took the positive y-axis as the north direction and the negative y-axis as the south direction. I tried to find the distance using d= speed x time for both axis and summing them up but that seems to be so wrong and don't know what else to do...Any help will be very much appreciated thanks..
 
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Displacement is not distance traveled. Review the definition of what displacement is...
 
cyby said:
Displacement is not distance traveled. Review the definition of what displacement is...

Yeah, i know displacement is change in position... but am trying to find the distance first; because the question asks for both distance and displacement and i think we need to find the distance before we can get the displacement.. isn't that right?
 
fiziks09 said:

The Attempt at a Solution


First of all i converted from m/s to km/h. I took the positive y-axis as the north direction and the negative y-axis as the south direction. I tried to find the distance using d= speed x time for both axis and summing them up but that seems to be so wrong and don't know what else to do...Any help will be very much appreciated thanks..
Please show the work you did, and the answers you got.
 
If he goes 30m/s for 30 minutes, how many seconds are in 30 minutes. Find that and multiply. Then do the same for the next part.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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