Calculating Acceleration from Change in Velocity and Distance

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SUMMARY

The discussion focuses on calculating the acceleration of an electron that transitions from an initial velocity of 1.0 × 104 m/s to a final velocity of 4.0 × 106 m/s over a distance of 1 cm. Using the kinematic equation v2 = u2 + 2ax, the acceleration can be determined by rearranging the formula to solve for 'a'. The average velocity is also calculated to find the time taken to traverse the 1 cm distance, which is essential for determining acceleration using the formula a = Δv/Δt.

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  • Understanding of kinematic equations, specifically v2 = u2 + 2ax
  • Basic knowledge of acceleration and velocity concepts
  • Familiarity with average velocity calculations
  • Ability to manipulate algebraic equations
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An electron with initial velocity v_{x}_{o} = 1.0 \times 10^{4} meters/sec enters a region where it is electrically accelerated. It emerges with a velocity v_{x} = 4.0 \times 10^{6} meters/sec. What was its acceleration, assumed constant? The accelerated region is 1 cm. So acceleration is defined as \frac{\Delta v}{\Delta t}. How would I use the fact that the accelerated region is 1 cm long?

Thanks
 
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Calculate the time it takes for the electron to traverse that distance. (Hint: What's the average velocity?)

You can also make use of any formulas you may know describing the kinematics of uniformly accelerated motion.
 
use v^2 = u^2 + 2*a*x
where v = final velocity
u = initial velocity
a = acceleration
x = distance.
 

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