Motion in Polar Coordinates problem

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Homework Help Overview

The problem involves a particle described in polar coordinates with the equation r=be^[Zcot(a)]. The task is to demonstrate that the velocity and acceleration vectors form angles a and 2a with respect to the origin O.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive the velocity vector and expresses confusion about demonstrating the required angles. Another participant suggests simplifying the velocity expression and using the dot product to find the angles between vectors.

Discussion Status

Some guidance has been offered regarding the simplification of the velocity expression and the use of the dot product to determine angles. The discussion reflects an ongoing exploration of the problem without a clear consensus or resolution.

Contextual Notes

Participants note that Z represents theta, which is the angle the position vector makes with the x-axis, and that w is a constant derivative with respect to time. Constants B and a are also mentioned, but their roles in the problem remain under discussion.

Master J
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Been looking over past exam questions and came across this one. Its in polar coordinates:

A particle P describes the curve r=be^[Zcot(a)].

Show that the velocity and acceleration vectors have angles a and 2a with OP (O is the origin).

Z is actually theta, the angle the position vector makes with the x axis. Its derivative to time is w, a constant here. B and a are constants.


I'm stumped!


I work out v as: bcot(a)we^(Zcot(a)).[e_1] + bwe^('').[e_2]

Even with them worked out I am stumped as to show that^^^^

Any pointers?

Cheers guys!
 
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Hi Master J,

Master J said:
Been looking over past exam questions and came across this one. Its in polar coordinates:

A particle P describes the curve r=be^[Zcot(a)].

Show that the velocity and acceleration vectors have angles a and 2a with OP (O is the origin).

Z is actually theta, the angle the position vector makes with the x axis. Its derivative to time is w, a constant here. B and a are constants.


I'm stumped!


I work out v as: bcot(a)we^(Zcot(a)).[e_1] + bwe^('').[e_2]

I would suggest first simplifying this expression for v, using the expression for r given in the problem. Then, since they ask for the angle between two vectors, that suggests using the dot product (since one definition of the dot product explicitly includes the angle between the vectors). Do you get the answer?
 
SOlved! Thanks for the help.
 
Sure, glad to help!
 

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