Motion in Space: Velocity and Acceleration

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SUMMARY

The discussion focuses on calculating various aspects of motion in space, specifically for the vector function V(t) = (1+t)i + (t^2-2t)j. The velocity is determined as v'(t) = <1, 2(t-1)>, and the acceleration is given by a(t) = <0, 2>. The speed or length is calculated using the formula length = √(1 + 4(t-1)²), while the unit tangent vector is expressed as Unit Tangent = <1, 2(t-1)> / √(1 + 4(t-1)²). The discussion also addresses the need to clarify the components for tangential and normal vectors at t=2.

PREREQUISITES
  • Understanding of vector calculus
  • Familiarity with derivatives and vector functions
  • Knowledge of unit vectors and their applications
  • Basic proficiency in algebraic manipulation
NEXT STEPS
  • Study the derivation of tangential and normal components of vectors
  • Learn about the application of the dot product in vector projections
  • Explore the concept of curvature in motion along a path
  • Investigate the implications of acceleration in two-dimensional motion
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Students studying physics or mathematics, particularly those focusing on vector calculus, as well as educators seeking to enhance their understanding of motion in space.

Physicsnoob90
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Homework Statement


For V(t) = (1+t)i + (t^2-2t)j find:

1. velocity
2.Acceleration
3. speed/length
4. Unit Tangent
5. tangential component
6. normal component at t=2

Homework Equations


The Attempt at a Solution



1. v'(t) = <1,2t-2> = <1, 2(t-1)>
2. a(t) = <0,2>
3. length = Square root of (1+4(t-1)^2)
4. Unit Tangent = <1,2(t-1)> / square root (1+4(t-1)^2)
from here I'm stuck trying to find the tangential component and normal component. [/B]
 
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Physicsnoob90 said:

Homework Statement


For V(t) = (1+t)i + (t^2-2t)j find:

1. velocity
2.Acceleration
3. speed/length
4. Unit Tangent
5. tangential component
6. normal component at t=2

Homework Equations


The Attempt at a Solution



1. v'(t) = <1,2t-2> = <1, 2(t-1)>
2. a(t) = <0,2>
3. length = Square root of (1+4(t-1)^2)
4. Unit Tangent = <1,2(t-1)> / square root (1+4(t-1)^2)
from here I'm stuck trying to find the tangential component and normal component. [/B]

First decide: normal and tangential component of WHAT? In general, if you have two vectors ##\vec{a}, \vec{b}## the component ##\vec{a}_{||}## of ##\vec{a}## parallel to ##\vec{b}## and the component ##\vec{a}_{\perp}## perpendicular to ##\vec{b}## are
[tex]\vec{a}_{||} = \frac{\vec{a} \cdot \vec{b}}{\vec{b} \cdot \vec{b}} \vec{b} \\<br /> \vec{a}_{\perp} = \vec{a} - \frac{\vec{a} \cdot \vec{b}}{\vec{b} \cdot \vec{b}} \vec{b}[/tex]
 

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