- #1

ppxrare

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## Homework Statement

A basketball star covers 2.40 m horizontally in a jump to dunk the ball (see figure). His motion through space can be modeled precisely as that of a particle at his center of mass. His center of mass is at elevation 1.02 m when he leaves the floor. It reaches a maximum height of 1.90 m above the floor and is at elevation 0.910 m when he touches down again.

(a) Determine his time of flight (his "hang time").

(b) Determine his horizontal velocity at the instant of takeoff.

(c) Determine his vertical velocity at the instant of takeoff.

(d) Determine his takeoff angle.

(e) For comparison, determine the hang time of a whitetail deer making a jump (see figure above) with center-of-mass elevations yi = 1.20 m, ymax = 2.45 m, and yf = 0.800 m.

I tried to think about the question but I'm not getting anywhere, by time of flight do they mean time till he reaches max height or till he reaches hoop and comes down again and I am confused by the elevation