Motion on Inclined Plain with Pulley

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SUMMARY

The discussion focuses on calculating the tension in a string and the acceleration of a cart on an inclined plane with a pulley system. The cart weighs 0.5 kg, and the mass attached to the pulley is 0.1 kg, with the incline set at a 20-degree angle. The user initially calculated the tension as 0.6582 N and acceleration as 3.21 m/s² but expressed doubt about the accuracy of these results. A suggestion was made to ensure consistent sign assignment in the equations, specifically noting that the force on the weight should be expressed as 0.1a = T - 0.98.

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  • Understanding of Newton's Second Law (Fg = ma)
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magixx
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Homework Statement


Cart is on an inclined plain, attached to the cart is a weightless string going to a pulley attached to another mass. There is no friction.
Cart Weight: 0.5Kg
Mass Weight: 0.1Kg
Plain Angle: 20 Degrees
Diagram: See below

Question: Determine Tension in string and acceleration.

Homework Equations


Fg=ma

The Attempt at a Solution


http://img254.imageshack.us/img254/6286/physji3.jpg

With the two equations I then made them both equal 5a and then used elimination, I got T=0.6582N and a=3.21m/s.
I kinda doubt this is the right answer.
 
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magixx said:

Homework Statement


Cart is on an inclined plain, attached to the cart is a weightless string going to a pulley attached to another mass. There is no friction.
Cart Weight: 0.5Kg
Mass Weight: 0.1Kg
Plain Angle: 20 Degrees
Diagram: See below

Question: Determine Tension in string and acceleration.

Homework Equations


Fg=ma

With the two equations I then made them both equal 5a and then used elimination, I got T=0.6582N and a=3.21m/s.
I kinda doubt this is the right answer.

Welcome to PF.

I think you need to be consistent in how you assign signs between the two equations.

The force on your weight should be more properly given by .1a = T - .98
 

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