- #1

loku

- 9

- 1

- Homework Statement
- A body is thrown vertically up from the top of a tower with a velocity of 5m/s. It reaches the ground after 5 sec. Find height of the tower.

- Relevant Equations
- S=ut+(1/2)at^2

u=5m/s

t=5sec

the height will be the displacement

s=ut - (1/2)gt^2

s=5*5-0.5*10* 25

s=-100m

But the answer is 273.6m

t=5sec

the height will be the displacement

s=ut - (1/2)gt^2

s=5*5-0.5*10* 25

s=-100m

But the answer is 273.6m