Motion under influence of a resistive force

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Homework Help Overview

The discussion revolves around the motion of a body influenced by a resistive force described by the equation F = -m*γ*vα. Participants are exploring the implications of different values of the dimensionless constant α on the time it takes for the motion to stop.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to derive the time it takes for the motion to stop based on the equation of motion and questions the validity of their result when α leads to a negative time. Other participants inquire about specific cases, such as α = 0 and α = 2, and whether these yield finite and positive times.

Discussion Status

Participants are actively engaging with the problem, checking assumptions and exploring different scenarios. Some have confirmed the correctness of the original poster's solution while raising further questions about the implications of various values of α. There is a recognition of certain values leading to non-physical results, prompting further inquiry.

Contextual Notes

Participants are considering the physical realism of the results based on the chosen values of α, particularly noting the implications of negative time and the conditions under which the motion ceases.

Ananthan9470
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No template because originally posted in wrong thread
Consider the 1d motion of a body under the influence of the force given by F = -m*γ*vα. m is mass, γ is a constant of appropriate dimension, v is velocity and α is dimensionless constant. The value of α for which the motion will come to a stop in finite time is to be calculated. I solved the equation of motion given by v'' = -γ*vα and got an equation for t given by t = (1/γ)*(V01-α)/(1-α); V0 is the initial velocity. According to this, for all γ>1, time is finite. But the sign of t is negative. Why is this happening? Am I doing something wrong?
 
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Your solution for t is correct. What do you get for t if ##\alpha = 0##? Is this a finite time? Is it positive?
 
Chestermiller said:
Your solution for t is correct. What do you get for t if ##\alpha = 0##? Is this a finite time? Is it positive?
For ##\alpha = 0## it is positive but what about something like α = 2? It is turning out to be negative unless I am mistaken. right?
 
Ananthan9470 said:
For ##\alpha = 0## it is positive but what about something like α = 2? It is turning out to be negative unless I am mistaken. right?
Yes. That's the region that is not physically realistic.

What do you get when ##\alpha = -1##? Is that a finite time? What do you get for v vs t in the special case when ##\alpha = 1##?
 

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