Mouse onto the edge of phonograph turntable

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Homework Help Overview

The discussion revolves around a physics problem involving a mouse on a rotating phonograph turntable. The mouse's mass, the radius of the turntable, and the angular speed are provided, with the question focusing on the work required for the mouse to move to the center while maintaining constant angular velocity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the implications of constant angular velocity on angular momentum and work. Questions arise about the relationship between rotational inertia and work, and the need to calculate centripetal force as the mouse moves inward.

Discussion Status

Participants are actively discussing the problem, with some suggesting methods to calculate the necessary force and work. There is a mix of interpretations regarding the equations involved, and while some clarity has been achieved, no consensus on a definitive approach has been reached.

Contextual Notes

The problem includes specific values for mass, radius, and angular speed, and participants are encouraged to clarify the full problem statement for better understanding. There is a focus on the assumptions regarding constant angular velocity and its effects on the forces involved.

tonit
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Homework Statement


mmouse = 0.06kg

r = 0.3m

\omega = 0.05 rad / s

Suppose angular speed does not change.
What is the work needed for the mouse to go to the center.

Homework Equations



Io\omegao = If\omegaf


The Attempt at a Solution



If \omega doesn't change ,then how can I use the above equation.

Since I of mouse would be equal to mr^2 then \omega would change. I am stuck here. Oh, and it's not a homework, it's a problem that I was stuck at some time ago. Thanks for any help
 
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tonit said:

Homework Equations



Io\omegao = If\omegaf


The Attempt at a Solution



If \omega doesn't change ,then how can I use the above equation.
You can't. If ω is fixed then angular momentum is not conserved.
 
So in this case would the work be equal to: mr^2 ?
 
tonit said:
So in this case would the work be equal to: mr^2 ?
That's an expression for rotational inertia, not work.

Can you please state the full problem as it was given?
 
A 60 gm mouse falls onto the outer edge of a phonograph turntable of radius 30 cm rotating at 33rev/min. How much work must it do to walk into the center post? Assume that the angular velocity of the turntable doesn't change.
 
Seems like you just need to find out the centripetal force that the mouse feels and then you'll have the work. Though I could be wrong.
 
hi tonit! :smile:
tonit said:
A 60 gm mouse falls onto the outer edge of a phonograph turntable of radius 30 cm rotating at 33rev/min. How much work must it do to walk into the center post? Assume that the angular velocity of the turntable doesn't change.

yes, work done is the integral of force "dot" displacement

so, first, what is the force needed, as a function of r ? :wink:
 
There is a centripetal acceleration associated with rotation at constant angular velocity, a_c = \omega^2 r. So if my suspicions are correct, you can interpret that as a force that must be overcome, F_c = m \omega^2 r
 
thanks to all of you. now it is all clear :D
 

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