Moving block on a moving incline

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SUMMARY

The discussion centers on the dynamics of a block on a moving incline, specifically addressing the complexities introduced when the incline itself is allowed to move on a frictionless surface. The initial solution using Newton's laws for static and frictionless cases is straightforward, but complications arise when considering the block's acceleration relative to the incline. The participant emphasizes the need for a collaborative approach to solving this problem rather than simply providing an answer, referencing concepts from classical mechanics.

PREREQUISITES
  • Newton's laws of motion
  • Understanding of friction and frictionless surfaces
  • Fundamentals of free body diagrams (FBDs)
  • Basic principles of acceleration and forces
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  • Study the dynamics of systems with moving components
  • Explore advanced applications of Newton's laws in non-inertial frames
  • Learn about the effects of acceleration on forces in inclined planes
  • Practice drawing and analyzing free body diagrams for complex systems
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Students of physics, mechanical engineers, and anyone interested in classical mechanics and the dynamics of moving systems will benefit from this discussion.

Living_Dog
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I have thought and thought about this problem for years and made no progress.

First off, the moving block on an incline plane has a simple solution using Newton's laws for both friction and no friction cases. But once the incline plane itself is allowed to move, on a frictionless surface, then my problem begins.

Now what I am asking for is someone to help me work through the solution rather than just handing me an answer. This is not for any homework. I saw it years ago (Taylor? Goldstein??) and have never thought of posting it here until now.


Thanks!

-LD
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Let the incline have acceleration f, which for simplicity is parallel to the ground.

Now let the block have acceleration a relative to the incline. Note that this will be parallel to the slope of the incline.

However, the total acceleration of the block will be f+a. What this means is that the block will in fact accelerate into the plane of incline, so the component of its weight on the incline, minus the inclines reaction force will be nonzero. In other words, the reaction from the incline will not entirely cancel out the component of weight.

Note that the incline will have two forces on it. It's weight, and the reaction force from the block.

Now, draw a picture.
 
Draw two separate FBD's.
 

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