# Moving Blocks Connected by a spring

1. Oct 26, 2008

1. The problem statement, all variables and given/known data
Moving blocks connected by a spring
Two identical 0.13 kg blocks (labeled 1 and 2) are initially at rest on a nearly frictionless surface, connected by an unstretched spring whose stiffness is 225 N/m, as shown in the upper diagram. Then a constant force of 8 N to the right is applied to block 2, and at a later time the blocks are in the new positions shown in the lower diagram. At this final time, the system is moving to the right and also vibrating, and the spring is stretched.

2. Relevant equations
KE= (1/2)mv^2
U= (1/2)kx^2

3. The attempt at a solution

What is the final translational kinetic energy of the real system?
What is the final vibrational kinetic energy of the real system?

I'm a little lost on how to find the two different kinetic energies since the problem doesnt give a final velocity. I found that the final total kinetic energy is .595 joules and that the total final potential energy is .045 joules, but i don't know to separate the two kinetic energies.

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2. Oct 27, 2008

### tiny-tim

Welcome to PF!

Hint: Call the positions of the two blocks x1 and x2.

Then x1 - x2 helps you find the PE, and x1 and x2 individually give you the KE.

And the work done is … ?

3. Oct 27, 2008

Thanks!
I found the work to be .64 joules and i used W=deltaK, but this gives me the total kinetic energy, and I'm trying to find the two different kinds of kinetic energy, Translation and vibrational.

4. Oct 27, 2008

### tiny-tim

I'm not sure what "vibrational KE" is … what definition are you using?

Anyway, given x1 and x2 (and its average, x3), there must be an expression for vibrational KE in terms of x1 x2 and x3.

5. Oct 27, 2008

Well there isn't any equation for finding the vibrational energy in my book, but this problem had a first part to it where it asked for the the translational kinetic energy for the blocks as a point particle system, which doesnt have the vibrational energy, which i found was the same for both the particle system and the real system, .55125 J. I figured this would work for finding the Vibrational Kinetic energy, but its wrong.
.55125+KEV=.64
KEV=.08875J

Last edited: Oct 27, 2008
6. Oct 27, 2008

### tiny-tim

How did you get the translational KE?

I expect they're defining vibrational KE as being total KE minus KE of the centre of mass … can't you get the latter from x1 and x2?

7. Oct 27, 2008