Graduate Multi-variable function depending on the Heaviside function

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The calculation of ∂/∂t(∫01 f(x,t,H(x-t)*a)dt) involves understanding the role of the Heaviside function and its derivative, which is the Dirac delta function. The Heaviside function introduces a piecewise nature to the integral, but the argument of the function f remains dependent on t. However, after integrating with respect to t, the variable t is eliminated from the expression. Therefore, the derivative of the integral with respect to t is effectively zero, as the integral does not retain t as a variable post-integration. This conclusion simplifies the analysis of the multi-variable function involving the Heaviside function.
CCMarie
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How can I calculate ∂/∂t(∫01 f(x,t,H(x-t)*a)dt), where a is a constant, H(x) is the Heaviside step function, and f is

I know it must have something to do with distributions and the derivative of the Heaviside function which is ∂/∂t(H(t))=δ(x)... but I don't understand how can I work with the Heaviside function being an argument of the function...
 
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And f is...?

Anyway, I don't think it matters. ##\int_0^1 f(...) dt## does not actually depend on ##t##. Once you do the integration with respect to ##t##, ##t## no longer appears as a variable. So the derivative is 0.
 

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