Multiple choice, magnetic force on the particle

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SUMMARY

The discussion centers on calculating the magnetic force acting on a charged particle using the formula F=qv×B. The user correctly identifies that the charge is negative, which influences the direction of the force. The calculation provided results in a force vector of (20i - 15j), but the user expresses confusion regarding the correct answer choice, which is indicated as D. The user seeks clarification on their approach and the application of the right-hand rule in this context.

PREREQUISITES
  • Understanding of the Lorentz force equation: F=qv×B
  • Familiarity with vector cross products
  • Knowledge of magnetic fields and their representation in physics
  • Proficiency in using the right-hand rule for determining force direction
NEXT STEPS
  • Review the properties of vector cross products in physics
  • Study the right-hand rule and its applications in electromagnetism
  • Explore examples of magnetic force calculations involving negative charges
  • Investigate the implications of charge polarity on force direction in magnetic fields
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone preparing for exams involving magnetic forces on charged particles.

Mdhiggenz
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Homework Statement



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Homework Equations





The Attempt at a Solution



I know that since the charge is negative qo*Vperpendicular would be traveling in the oppsite direction. Which by the right hand rule ultimately affects B.

So using the formula F=q0V(perpendicular)*B

= 1*5(4i-3j)
= (20i-15j)

I don't understand why the answer would be D.

Or maybe my approach to the problem was incorrect?

Thanks
 
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The equation is [itex]\vec{F}=q\vec{v}\times\vec{B}=-1C*5\hat{k}\frac{m}{s}\times(3\hat{i}-4\hat{j})T[/itex]. What is [itex](-1)(-4)\hat{k}\times\hat{j}[/itex]?
 

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