Multiplicity of s-dimensional Harmonic oscillator

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SUMMARY

The energy eigenvalues of an s-dimensional harmonic oscillator are defined by the equation ε_j = (j + s/2)ħω. The multiplicity of the jth energy level is calculated using the formula M_j = (j + s - 1)! / (j! (s - 1)!). This multiplicity represents the number of ways to distribute energy among the s dimensions, which can be approached as a combinatorial problem where the sum of the individual quantum numbers must equal j. The discussion emphasizes the need for a mathematical method to derive this multiplicity rather than relying solely on established results.

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Homework Statement


The energy eigenvalues of an s-dimensional harmonic oscillator is:

\epsilon_j = (j+\frac{s}{2})\hbar\omega

show that the jth energy level has multiplicity \frac{(j + s - 1)!}{j!(s - 1)!}

Homework Equations


partition function: Z = \Sigma e^{-( (j+\frac{1}{2})\hbar\omega)/kt)}
there should be a Sum over j there, but its not showing up.

The Attempt at a Solution


Besides for drawing a picture or writing out an expansion, I can't come up with a way to calculate this. Infact, no one that I have spoken to has had a good method of calculating this.

Im just wondering how I can get to this answer mathematically. Plenty of resources just state this as the degeneracy of an s dimensional oscillator, but I have yet to see how to calculate it.

Thanks in advanced for any help.
 
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I don't know how you might use the partition function for this. Anyway, how many different ways are there to excite the dimensional modes to obtain a given energy? For example, if the energy level is j=3 in 3-D, then there are three "sub-j"s, j1, j2 and j3, one for each dimension, and they must satisfy j1+j2+j3=j. So, you can have:
j1=0, j2=0, j3=3
j1=0, j2=1, j3=2
etc.
So, this is a basic combinatorics problem with a constraint: You must choose s numbers, and they must add up to j.
 

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