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I can't get this problem right and it's part of a web-based assignment that I have to submit. In order to get credit for the problem, all of my answers need to be right; I've tried many different times and I can't seem to figure out what I am doing wrong. Here it is with my explanations as to why I think I'm right; please, can someone find my mistake?
Find the following limits. If a limit diverges to infinity, state your answer as "INF" (without the quotation marks). If it diverges to negative infinity, state your answer as "MINF".If it diverges without being infinity or negative infinity, state your answer as "DIV".
lim(x,y)->(0,0) (3x^2 + y^2)/(x^4 + 5 y^4)
= DIV
Limit does not exist because if I try to go through different paths, I get different limits.
lim(x,y)->(0,3) ysin(x)/x
= 3
by separating the two functions y & sin(x)/x and evaluating them seperately
lim(x,y)->(5,0) (3x + ln(1+xy) ) / (1+x+y)
=15/6
just by plugging in the values (function is continuous everywhere)
lim(x,y)->(0,0) (x^2 * y^2) / (x^4 + 5y^4)
= DIV
Limit does not exist once again because of different paths I took = different limits
Thanks a lot =)
Find the following limits. If a limit diverges to infinity, state your answer as "INF" (without the quotation marks). If it diverges to negative infinity, state your answer as "MINF".If it diverges without being infinity or negative infinity, state your answer as "DIV".
lim(x,y)->(0,0) (3x^2 + y^2)/(x^4 + 5 y^4)
= DIV
Limit does not exist because if I try to go through different paths, I get different limits.
lim(x,y)->(0,3) ysin(x)/x
= 3
by separating the two functions y & sin(x)/x and evaluating them seperately
lim(x,y)->(5,0) (3x + ln(1+xy) ) / (1+x+y)
=15/6
just by plugging in the values (function is continuous everywhere)
lim(x,y)->(0,0) (x^2 * y^2) / (x^4 + 5y^4)
= DIV
Limit does not exist once again because of different paths I took = different limits
Thanks a lot =)