Multivariate Higher Order Derivatives

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SUMMARY

The discussion focuses on deriving relationships between higher order derivatives of a function f using the transformation h(u,v) = f(u+v, u-v). Participants confirm that f_{xx} - f_{yy} equals h_{uv} and f_{xx} + f_{yy} equals ½(h_{uu} + h_{vv}). The transformation involves converting variables from (u,v) to (x,y) using u = (x+y)/2 and v = (x-y)/2. Participants emphasize the importance of applying the chain rule effectively to navigate between these variable transformations.

PREREQUISITES
  • Understanding of partial derivatives and notation
  • Familiarity with the chain rule in multivariable calculus
  • Knowledge of higher order derivatives
  • Ability to manipulate and transform variables in calculus
NEXT STEPS
  • Study the application of the chain rule in multivariable calculus
  • Learn about higher order derivatives and their significance
  • Explore variable transformations in calculus, specifically in relation to partial derivatives
  • Practice problems involving the derivation of relationships between derivatives using transformations
USEFUL FOR

Students and educators in advanced calculus, particularly those focusing on multivariable functions and their derivatives. This discussion is beneficial for anyone looking to deepen their understanding of partial derivatives and variable transformations.

Yagoda
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Homework Statement


Let h(u,v) = f(u+v, u-v). Show that f_{xx} - f_{yy} = h_{uv} and f_{xx} + f_{yy} = \frac12(h_{uu}+h_{vv}).


Homework Equations





The Attempt at a Solution


I'm always confused on how to tackle these types of questions because there isn't an actual function to differentiate.
So I am assuming here that x = u+v and y = u-v and going from there. So I need to find the first partial with respect to x, which might be something like f_x = \frac{\partial f}{\partial(u+v)} since I need to get it in terms of u and v, but this doesn't seem right. What sort of approach do I need to use on these questions?

Edit: What I've done now is write h_{uv} = \frac{\partial}{\partial v}\frac{\partial h}{\partial u} = \frac{\partial}{\partial v} ( \frac{\partial f}{\partial x} \frac{\partial x}{\partial u} + \frac{\partial f}{\partial y} \frac{\partial y}{\partial u}) =\frac{\partial}{\partial v} (\frac{\partial f}{\partial x} + \frac{\partial f}{\partial y}). I'm having trouble converting from u's and v's to x's and y's.
 
Last edited:
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u=\frac{x+y}{2} and v=\frac{x-y}{2} so f(x,y)=h(\frac{x+y}{2},\frac{x-y}{2})

So we have:

<br /> f_x=h_u u_x+h_v v_x \Rightarrow f_x=\frac{1}{2}h_u+\frac{1}{2}h_v

<br /> f_{xx}=\frac{1}{2}(h_{uu}u_x+h_{uv}v_x+h_{vu}u_x+h_{vv}v_x)<br />

I think you can continue yourself.
 
Yagoda said:

Homework Statement


Let h(u,v) = f(u+v, u-v). Show that f_{xx} - f_{yy} = h_{uv} and f_{xx} + f_{yy} = \frac12(h_{uu}+h_{vv}).

Homework Equations


The Attempt at a Solution


I'm always confused on how to tackle these types of questions because there isn't an actual function to differentiate.
So I am assuming here that x = u+v and y = u-v and going from there. So I need to find the first partial with respect to x, which might be something like f_x = \frac{\partial f}{\partial(u+v)} since I need to get it in terms of u and v, but this doesn't seem right. What sort of approach do I need to use on these questions?

Edit: What I've done now is write h_{uv} = \frac{\partial}{\partial v}\frac{\partial h}{\partial u} = \frac{\partial}{\partial v} ( \frac{\partial f}{\partial x} \frac{\partial x}{\partial u} + \frac{\partial f}{\partial y} \frac{\partial y}{\partial u}) =\frac{\partial}{\partial v} (\frac{\partial f}{\partial x} + \frac{\partial f}{\partial y}). I'm having trouble converting from u's and v's to x's and y's.

For thinking about these things it's sometimes good to think about the operators without worrying about the functions. Define, for example, ##\partial_u(F)=\frac{\partial F}{\partial u}##. Then wouldn't it be true that ##\partial_u=\partial_x+\partial_y## and ##\partial_v=\partial_x-\partial_y## from the chain rule? It can save you a lot of texing and even spare some confusion. It's kind of the same as your underscore notation for partial derivatives.
 
Last edited:

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