Multivariate piecewise fxn continuity and partial derivative

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SUMMARY

The discussion focuses on the continuity of the multivariate piecewise function defined as f(x,t) for t >= 0 and its behavior for t < 0. The function is defined in segments, with specific expressions for different ranges of x. The continuity proof utilizes an epsilon-delta approach, demonstrating that f is continuous in R^2. Additionally, the derivative g'(0) is shown to be non-equal to the integral of f(x,0) over the interval from -1 to 1, highlighting the complexities introduced by the piecewise nature of f.

PREREQUISITES
  • Understanding of multivariable calculus, specifically continuity and derivatives.
  • Familiarity with piecewise functions and their properties.
  • Knowledge of epsilon-delta definitions for continuity proofs.
  • Experience with integration techniques, particularly in the context of defining functions through integrals.
NEXT STEPS
  • Study the epsilon-delta definition of continuity in multivariable functions.
  • Learn about piecewise function analysis and its implications on continuity and differentiability.
  • Explore the concept of partial derivatives and their computation in piecewise contexts.
  • Investigate the properties of integrals of piecewise functions and their applications in defining new functions.
USEFUL FOR

Mathematicians, students of calculus, and anyone involved in advanced mathematical analysis, particularly those working with piecewise functions and multivariable calculus.

vchurchill
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1. Problem

Define a function:

for t>=0, f(x,t) = { x for 0 <= x <= sqrt(t), -x + 2sqrt(t) for sqrt(t) <= x <= 2sqrt(t), 0 elsewhere}

for t<0 f(x,t) = - f(x,|t|)

Show that f is continuous in R^2. Show that f_t (x, 0) = 0 for all x.

Then define g(t) = integral[f(x,t)dx] from -1 to 1. Show g(t) = t for |t|<1/4, and hence g'(0) != integral[f(x,0)dx] from -1 to 1.

2. Solution attempt

For the first part, I used an epsilon-delta proof:

For all epsilon > 0 there exists 0<delta=epsilon/3 s.t. |x-x0|<eps/3 implies |f(x)-f(x0)|<eps. Checking for both important pieces of f, this works.

Then I computed f_t(x,t) = { 1/sqrt(t) for sqrt(t) <= x <= 2sqrt(t), and 0 elsewhere}. I do not understand how f_t(x,0) then is equal to 0 for all x since it would seem that for x = 0 we have f_t(0,0) = 1/sqrt(0) = ??

Then the last part... the piecewise-ness of this fxn makes it extremely difficult to conceptualize and get a general g(t), so I'm guessing I should double integrate over -1/4 to 1/4 for t and -1 to 1 for x. Does this make sense?

Thanks for your help.
 
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