Mutual Inductance between two conductors

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Jason-Li
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Homework Statement
The mutual inductance between two circuits as shown is 0.2 μH.
It may be assumed that (R1 + RL1) >> ωL1 and that (R2 + RL2) >>ωL2.

(a) Estimate the crosstalk voltage at the load of circuit B when the signal
source of circuit A is V1 = 1 V at 1 GHz.

(b) Plot the crosstalk voltage (at the load of circuit B) as a function of
frequency.
Relevant Equations
(R1 + RL1) >> ωL1 and (R2 + RL2) >>ωL2.
1622463823984.png

Hello hope everyone at PF are keeping well!

Looking at this problem but don't know if I have oversimplified it and my final answer doesn't seem right?
So I drew the equivalent circuit:

1622462669994.png
1622462622905.png

Then went onto calculate:
I1 = 1/(R1+RL1) = 0.01A
ω = 2πf = 2π*109 rads-1
so then with Vi being the inducted voltage:
Vi = jω * M * I1 = 2π*109 * 0.2*10-6*0.01 = 12.566V This seems a bit high?

I also did the classic ohms law and did VL2 = Vi / (R2+RL2) * R2 = 9.643V to get the answer for (a)? I am really unsure if I have approached this correctly, any help would be greatly appreciated.

Then for part (b) I was just going to plot a straight line as the function is
Vi= jω*M*I1 I would change this to
Vi = (2π*M*I1)*f which is the same as y=mx ?
 

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tech99 said:
I think the primary current is flowing through M, which has a large reactance. So I1 = V1/omega M (approx).

I think as it's mutual inductance current I1 won't be altered by M, but will effect M?

I have calculated I1 and then from that I can calculate the mutual inducted voltage?