Mutual inductance in a circuit.

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SUMMARY

The discussion focuses on deriving the Thevenin Equivalent Circuit (TEC) between terminals "ab" in a circuit involving mutual inductance. The user initially calculated the mutual inductances for the coils, resulting in a Thevenin resistance of -60 + 60j and a Thevenin voltage of 9 + 41j volts. However, the expected results are Rth = 60 + 60j and Vth = 9 + 51j. The confusion arises from the treatment of the capacitor, which does not contribute to mutual inductance and is instead analyzed in its phasor form.

PREREQUISITES
  • Understanding of Thevenin Equivalent Circuit (TEC)
  • Knowledge of mutual inductance in RLC circuits
  • Familiarity with phasor representation of capacitors
  • Ability to apply Kirchhoff's Voltage Law (KVL)
NEXT STEPS
  • Study Thevenin's Theorem in depth
  • Learn about mutual inductance calculations in RLC circuits
  • Explore phasor analysis for capacitors in AC circuits
  • Review Kirchhoff's Voltage Law (KVL) applications in complex circuits
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing RLC circuits and Thevenin equivalents.

anthonych414
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Homework Statement



Derive TEC between terminals "ab".

Homework Equations





The Attempt at a Solution



I figured I'd add the mutual inductances to the inductors, and solve it as a normal RLC circuit, since no current is passing through the 80j coil, it's inductance wouldn't change. The 50j coil becomes an 80j coil (50j + 30j) and the 40j coil becomes a 70j coil (40j + 30j). Setting the voltage source to zero yields a thevenin resistance of -60 + 60j and KVL yields to a Thevenin voltage of 9 + 41j volts. However the answer says Rth = 60 + 60j and Vth = 9 + 51j. Can anyone help me identify where I went wrong? Thank you in advance.
 

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anthonych414 said:

Homework Statement



Derive TEC between terminals "ab".

Homework Equations


The Attempt at a Solution



I figured I'd add the mutual inductances to the inductors, and solve it as a normal RLC circuit, since no current is passing through the 80j coil, it's inductance wouldn't change. The 50j coil becomes an 80j coil (50j + 30j) and the 40j coil becomes a 70j coil (40j + 30j). Setting the voltage source to zero yields a thevenin resistance of -60 + 60j and KVL yields to a Thevenin voltage of 9 + 41j volts. However the answer says Rth = 60 + 60j and Vth = 9 + 51j. Can anyone help me identify where I went wrong? Thank you in advance.
First of all you will have to explain the question. What does TEC stand for?

Where do you take into account the capacitor?

AM
 
Andrew Mason said:
First of all you will have to explain the question. What does TEC stand for?

Where do you take into account the capacitor?

AM

TEC stands for Thevenin Equivalent Circuit, and the capacitor does not undergo mutual inductance, so I use its phasor form to find the equivalent thevenin resistance like I would with a resistor.
 

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