What work have you done so far? Can you write the relationship between C, Q and V? How do you determine C for three capacitors in series? In parallel?meLzee said:Homework Statement
THREE CAPACITORS HAVING CAPACITANCE 8.4 F, 8.4 F, 4.2 F ARE CONNECTED IN SERIES ACROSS A 36 V POTENTIAL DIFFERENCE. THE CAPACITORS ARE DISCONNECTED FROM THE POTENTIAL DIFFERENCE WITHOUT ALLOWING THEM TO DISCHARGE. THEY ARE THEN RECONNECTED IN PARALLEL WITH EACH OTHER, WITH THE POSITIVELY CHARGED PLATES CONNECTED TOGETHER. WHAT IS THE VOLTAGE ACROSS EACH CAPACITOR IN PARALLEL COMBINATION?
PLEASE HELP ME WITH THIS. THANX.
Capacitance is the ability of a material or system to store electrical charge. In terms of your problem, capacitance can affect the flow of electricity and the ability of a system to hold a charge.
Capacitance can be calculated using the equation C = Q/V, where C is capacitance, Q is charge, and V is voltage. It can also be measured using a capacitance meter or multimeter.
Common problems with capacitance include unwanted interference in electrical circuits and the inability to hold a charge. These can be solved by using shielding techniques, using materials with higher dielectric constants, and using capacitors with higher capacitance values.
The size and shape of a capacitor can greatly affect its capacitance. Capacitance is directly proportional to the surface area of the plates and inversely proportional to the distance between them. Therefore, larger plates and a smaller distance between them will result in a higher capacitance.
Yes, capacitance can be increased or decreased by changing the physical parameters of a capacitor, such as the size, shape, and distance between plates. It can also be increased by adding more capacitors in parallel or decreased by adding them in series.