N/CWhat is the Electric Field Strength to Reduce String Tension to Zero?

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SUMMARY

The electric field strength required to reduce the tension in a string holding a piece of aluminum foil to zero is calculated to be 1.56 x 105 N/C. This is derived from the equation E = mg/q, where m is the mass of the foil (4.3 x 10-2 kg), g is the acceleration due to gravity (9.81 m/s2), and q is the charge on the foil (2.7 µC). The net force acting on the foil must equal zero, leading to the conclusion that the electric force must exactly counterbalance the weight of the foil.

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  • Familiarity with mass and weight calculations
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Homework Statement



A piece of aluminum foil of mass 4.3 10-2 kg is suspended by a string in an electric field directed vertically upward. If the charge on the foil is 2.7 µC, find the strength of the field that will reduce the tension in the string to zero.



Homework Equations



E= Fe/q
F=ma


The Attempt at a Solution



So what I can gather is I need to find the net force acting on the piece of foil. I know that the T should be equal to 0 and that the foil isn't accelerating. So what forces would I be left with? I'm trying to solve for Fe right here, correct?
 
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nevermind, figured it out.
 
first, equation of electric field strength is force per unit charge E = F / q

or F = qE

the force generated by electric field needs to cancel out the weight of foil exactly, thus

mg = F

mg = qE

rearrange:

E = mg / q

E = 4.3e-2 * 9.81 / 2.7e-6

E = 1.56e5 N/C (1.56 x 10^5)
 

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