- #1

velouria131

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## Homework Statement

Two uniformly charged spheres are suspended by strings of length L from vertically adjustable supports. The spheres are in static equilibrium.

The angles with respect to the vertical are Q=14.9°, and T=20.7°.

The tension in the string supporting sphere Z (Z with respect to angle T, W is the other sphere and hangs with respect to angle Q) is 2.41E-5 N. Calculate the tension in the other string.

## Homework Equations

Fe = k (q1 * q2 / (r) ^ 2)

Fg = mg

## The Attempt at a Solution

Alright, here is a brief overview of what I have done. I first recognized that the system was in static equilibrium. Thus, for each sphere I wrote equations representing the force components, and set each equation to zero. Each sphere operates under the same conditions.

Sphere Z lies to the left (T is force due to tension, Fe is force due to Electric repulsion)

Tx = Tcos∅

Ty = Tsin∅

T = 2.41E-5 N

0 = Tx - Fe

0 = Ty - mg

Sphere W lies to the right:

Tx = Tcostheta

Ty = Tsintheta

0 = -Tx + Fe

0 = Ty - mg

So, I recognize that in each case, the x-component of the tension in each string is equivalent. This makes sense because the forces on each sphere with respect to the x-axis are due to the electric force. This force has an equal and opposite effect. I cannot figure out how to find the total tension in the second string, even though I know the x component etc. Any help in progressing from this point would be greatly appreciated.