MHB Nabeela Zubair's Question on Facebook (Counting Problem)

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    Counting problem
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To solve the problem of choosing 2 different colors from 10 options, the first color has 10 possibilities, and the second color has 9, leading to a total of 90 combinations. However, since each combination is counted twice (e.g., A and B is the same as B and A), the total must be divided by 2, resulting in 45 unique combinations. This can also be represented using the binomial coefficient formula, which confirms that the number of ways to choose 2 colors from 10 is 45. The discussion emphasizes the importance of accounting for repetitions in combination problems. Understanding these principles is crucial for solving similar combinatorial questions.
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Nabeela Zubair on Facebook writes:

How I can solve this problem?

Students are choosing 2 colors to be used as school colors. There are 10 colors from which to choose. How many different ways are there to choose 2 different colors?

Total Colors 3 4 5 6 7 8 9 10
# of 2-color Comb. 3 6 10
 
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Sudharaka said:
Nabeela Zubair on Facebook writes:

How I can solve this problem?

Students are choosing 2 colors to be used as school colors. There are 10 colors from which to choose. How many different ways are there to choose 2 different colors?

Total Colors 3 4 5 6 7 8 9 10
# of 2-color Comb. 3 6 10

Hi Nabeela, :)

For the first color yo have 10 possibilities. After choosing the first color the second one sould be something different, so there are 9 possibilities for the second one. So by the multiplication principle there are \(10\times 9\) total possibilities for choosing the two colors. But then there are repetitions involved here. That is we have counted each combination twice. If A and B are two colors we have counted A first, B second as well as B first, A second. Therefore the answer should be divided by two to get the number of combinations.

\[\frac{10\times 9}{2}=45\]

This idea can be generalized using the binomial coefficient.

\[\binom {10}{2}=\frac{10!}{2!\,8!}=\frac{10\times 9}{2}=45\]
 
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