Natural Frequency for torsional vibration

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SUMMARY

The discussion focuses on calculating the natural frequency for torsional vibration of a fixed-fixed beam using the formula =1/2*3.142 sqrt(K*g/mr^2) hz, where K is defined as K=J*G/L, G is the modulus of rigidity, g is the acceleration due to gravity (386.4 in/s²), and m is the mass hanging on the beam at distance 'r' from the longitudinal axis. A question is raised about the impact of changing the beam configuration from fixed-fixed to fixed-free. It is concluded that if the beam is considered massless, the equation for a cantilever beam should apply, as the unrestrained section experiences no torsional stress.

PREREQUISITES
  • Understanding of torsional vibration principles
  • Familiarity with the modulus of rigidity (G)
  • Knowledge of fixed-fixed and fixed-free beam configurations
  • Basic grasp of dynamics and mass distribution
NEXT STEPS
  • Research the natural frequency calculations for cantilever beams
  • Explore the effects of beam configuration changes on vibration analysis
  • Study the implications of mass distribution on torsional vibration
  • Learn about the application of the modulus of rigidity in structural analysis
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Mechanical engineers, structural analysts, and students studying dynamics and vibration analysis will benefit from this discussion.

har_rai
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I am trying to calculate natural frequency for torsional vibration of fixed fixed beam using following formula.

=1/2*3.142 sqrt(K*g/mr^2) hz

Where K=J*G/L

and G=Modulus of rigidity

g=acceleration due to gravity=386.4 in/se2

m=mass hanging on the beam at distance 'r' from the longitudenal axis

My question is how does the equation above (if its right) is affected if I change the beam from fixed fixed to fixed -free.

thanks
 
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I can't verify your equation, but, if the beam is considered massless in this calculation, then the equation for a cantilever beam of length 'r' should apply (I don't have a reference for that equation) since the unrestrained section of the beam suffers no torsional stress, assuming the simply supported end is the equivalent of a supported frictionless rotational bearing.
 

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