Solving Natural Log: Round and Round I Go...

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To solve the equation ln(x+4)=2, the correct approach begins with exponentiating both sides to eliminate the natural logarithm, resulting in e^2 = x + 4. The next step is to isolate x by subtracting 4 from both sides, leading to x = e^2 - 4. The initial confusion arose from missteps in the manipulation of the equation, but the solution process is straightforward once the correct steps are followed. This highlights the importance of carefully tracking each transformation in logarithmic equations. The final solution is x = e^2 - 4.
member38644
when trying to solve

ln(x+4)=2

i tried this

ln(x+4)=2
e^2=(x+4)
ln e^2=ln(x+4)
2=ln(x+4)

and round and round i go... where do i start to go wrong?
 
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Welcome to physicsforums fieldlandman,

you actually went the right way till the second line:

fieldlandman said:
when trying to solve

ln(x+4)=2

i tried this

ln(x+4)=2
e^2=(x+4)

Continue there with solving FOR x!
 
thanks!

that was it! thanks!
 

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