1. The problem statement, all variables and given/known data The relaxed eyes of a patient have a refractive power of 50.1 diopters. (For the purposes of this problem, treat the eye as a single-lens system, with the retina 2.40 cm from the lens.) (a) Is the patient nearsighted or farsighted? (b) If the patient is nearsighted, find the far point. If this person is farsighted, find the near point. 2. Relevant equations 1/f = 1/d0 + 1/di 3. The attempt at a solution I know that the person is nearsighted. I guess where I'm going wrong is by thinking that the lens is a pair of glasses 2.40 cm in front of the eye, which is all the problems I have done so far. I have been using 1/50.1 to get f and converting it to centimeters where f = 1.9960 cm. What I use to get my answer: F is the far point. 1/f = 1/infinity + 1/(F-2.40) The answer I get, 4.3960 cm is wrong. Also, when I make di negative since it should be in front of the eye, I get .4039 which is also wrong.