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In (1D) quantum mechanics we deal with wavefunctions ##\psi(x)## belonging to ##L^{2}(\mathbb{R}) ##. We then have the position and momentum operators $$\hat{x}=x, \quad\hat{p}=-i\hbar\frac{\partial}{\partial x},$$
with the canonical commutation relation ##[\hat{x},\hat{p}]=i\hbar##. The textbooks then use the variance to prove the Uncertainty principle ##\sigma_{x}\sigma_{p}\geq\frac{\hbar}{2}.##
So far, so good. However, consider the position-momentum wavefunctions ##\psi(x,p)## belonging to ##L^{2}(\mathbb{R}^{2}) ##. We can define the prequantization operators $$\hat{x}_{pre}=i\hbar\frac{\partial}{\partial p}+x, \quad\hat{p}_{pre}=-i\hbar\frac{\partial}{\partial x},$$
and they also obey the canonical commutation relation ##[\hat{x}_{pre},\hat{p}_{pre}]=i\hbar.## The thing is, there is no position-momentum uncertainty principle at this level, and ##\psi(x,p)## is allowed to be as narrow in phase space as we want.
Why? What necessary condition for the uncertainty principle is missing at the prequantization level?
with the canonical commutation relation ##[\hat{x},\hat{p}]=i\hbar##. The textbooks then use the variance to prove the Uncertainty principle ##\sigma_{x}\sigma_{p}\geq\frac{\hbar}{2}.##
So far, so good. However, consider the position-momentum wavefunctions ##\psi(x,p)## belonging to ##L^{2}(\mathbb{R}^{2}) ##. We can define the prequantization operators $$\hat{x}_{pre}=i\hbar\frac{\partial}{\partial p}+x, \quad\hat{p}_{pre}=-i\hbar\frac{\partial}{\partial x},$$
and they also obey the canonical commutation relation ##[\hat{x}_{pre},\hat{p}_{pre}]=i\hbar.## The thing is, there is no position-momentum uncertainty principle at this level, and ##\psi(x,p)## is allowed to be as narrow in phase space as we want.
Why? What necessary condition for the uncertainty principle is missing at the prequantization level?