Just want to see if I did everything right. I'm notorious for simple mistakes. 1. The problem statement, all variables and given/known data A 100kg man concerned about his weight decides to weigh himself in an elevator. He stand on a bathroom scale in an elevator that is moving upward at 3.0 m/s. As the elevator reaches his floor, it slows to a stop. If the elevator slows to a stop over a distance of 2.0m, what is the reading on the bathroom scale? 2. Relevant equations I used F = ma v2 = v1 + a12(t2 - t1) r2 = r1 + v1(t2 - t1) + (1/2)(a12)((t2-t1)^2) 3. The attempt at a solution Ok I know that I needed to find the force of the scale. to find that I needed the net force, since I have the force of the gravity on the guy (100*9.8 = 980N) But to find that I needed the acceleration. thus with v2 = v1 + a12(t2-t1) I got this 0 = 3 + a12(t2 - 0) -3 = a12(t2) a12 = -3/t2 I plugged that into r2 = r1 + v1(t2-t1) + (1/2)(a12)((t2-t1)^2) 2 = 0 + 3(t2 - 0) + (1/2)(-3/t2)((t2-0)^2) 2 = 3t2 - (3/2)(1/t2)(t2^2) *Canceling I get 2 = 3t2 - 3t2/2 4 = 6t2 - 3t2 3t2 = 4 t2 = 4/3 Plugging back into a12 I get a12 = -3/(4/3) a12 = -9/4 Thus the net Force = 100(-9/4) = -225N Which means Fsacle = -225 - 980 = -1205N Making the scale read 1205N since it can only do positive right?