Need a setup for a fiction problem

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To solve the friction problem involving a large cube and a small cube, it's essential to analyze the forces acting on both cubes. The large cube, with a mass of 25 kg, is accelerated by a force P on a frictionless surface, while the small cube (4.0 kg) is at risk of sliding down due to gravity unless sufficient static friction is present. The coefficient of static friction between the cubes is 0.17, which is crucial for determining the minimum force P required to prevent sliding. Drawing free body diagrams (FBDs) for both cubes will help visualize the forces, including the normal force and weight acting on the small cube, which must be balanced for it to remain in static equilibrium. Ultimately, the force P must equal the normal force exerted by the small cube on the large cube to ensure stability.
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Need a setup for a friction problem

I know the concept of this problem but i don't know how to set it up...

'A large cube (mass= 25 kg) being accelerated across a horizontal frictionless surface by a horizontal force P. A small cube (mass= 4.0 kg) is in contact with the front surface of the large cube and will slide downward unless P is sufficiently large. The coefficient of static friction between the cubes is 0.17. What is the smallest magnitude that P can have in order to keep the small cube from sliding downward?'

Thanks in advance
 
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anyone please help me
 
P of the box needs to equal the normal force of the little box onto the big box. Draw two FBDs. On of a little box showing the effects of friction, a normal force and weight. Remember, the little box is in static equalibrium when referenced to the big box. The entire two box system may be accelerating due to force P but the comparison of the two boxs should help you figure this out.

Draw a FBD of the big box as well. The N of the little box onto the big one equals the N of the big box onto the little BTW.

Good luck.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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