Coefficient of the static friction homework

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SUMMARY

The discussion centers on calculating the minimum force P required to prevent a small cube from sliding down a larger cube due to static friction. Given a mass of 25 kg for the large cube and 4.0 kg for the small cube, the coefficient of static friction between them is 0.71. The calculated force P is 400 N, which is confirmed as correct by participants in the discussion. The importance of showing work in problem-solving is emphasized to facilitate assistance from others.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static friction and its coefficient
  • Ability to perform basic calculations involving mass and force
  • Familiarity with free-body diagrams
NEXT STEPS
  • Review the principles of Newton's second law of motion
  • Study the calculations for static friction in detail
  • Learn how to create and interpret free-body diagrams
  • Explore real-world applications of static friction in engineering
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Students in physics, educators teaching mechanics, and anyone interested in understanding the principles of static friction and force calculations.

touma
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A large cube with a mass of 25 kg is being accelerated across a horizontal frictionless surface by a horizontal force P. A small cube with a mass of 4.0 kg is in contact with the front surface of the large cube and will slide downwards unless P is sufficiently large. The coefficient of the static friction between the cubes is 0.71. What is the smallest magnitude that P can have in order to keep the small cubbe from cliding downward?


I got an answer of 4.0 x 10^2 N. But I am unsure if that is correct. Can someone try this? And show work please? :bugeye:
 
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touma said:
Can someone try this? And show work please? :bugeye:

It really does not work that way here. You show your work and then people will help you.
 

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