Need help - about Coulomb's Law and SHM

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SUMMARY

The discussion centers on demonstrating that a particle with negative charge (-q) placed between two fixed positive charges (+Q) exhibits simple harmonic motion (SHM) when displaced. The net force acting on the particle is calculated using Coulomb's Law, resulting in the equation F = - (qQd) / [4(π)(z)(y² + (0.5d)²)]^(3/2) = ma, where z represents permittivity and y is the displacement. To confirm that acceleration (a) is proportional to the negative of displacement (y), the total net force must be recalculated to derive the relationship a = -ω²y.

PREREQUISITES
  • Coulomb's Law and its application in electrostatics
  • Understanding of simple harmonic motion (SHM) principles
  • Basic calculus for force and motion analysis
  • Knowledge of permittivity in electrostatics
NEXT STEPS
  • Review the derivation of Coulomb's Law and its implications in electrostatic systems
  • Study the mathematical formulation of simple harmonic motion and its characteristics
  • Learn about the concept of effective force in systems with multiple charges
  • Explore the relationship between force, mass, and acceleration in dynamic systems
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Students and educators in physics, particularly those focusing on electrostatics and mechanics, as well as anyone interested in the mathematical foundations of simple harmonic motion.

elvisphy
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need help -- about Coulomb's Law and SHM

Two positive charges +Q are held fixed a distance d apart.
A particle of negative chage -q and mass m is placed midway between them, then is given a small displacement perpendicular to the line joining them and released. Show that the particle describes simple harmonic motion and find the period.
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i've found that the net force acting on the -q is
F = - (qQd) / [4(pai)(z)(y^2 + (0.5d)^2)]^(3/2) = ma
where z is the permittivity, and y is the displacement of -q

how i can show that a = - w^2 y?
 
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Well, you need to redo the calculation of the total net force.

Daniel.
 

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