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## Homework Statement

Two boxes are connected by a cord running over a pulley. Box A sits on a table and has a mass of 5.0 kg while box B hangs

freely and has a mass of 2.0 kg. Box A moves to the right and box B moves

downwards. If the coeﬃcient of kinetic friction between box A and the table is

0.20, what is the acceleration of the system and the tension in the cord? You

may assume that the cord remains taut and does not stretch.

## Homework Equations

F=ma

fk=mu*Fn

## The Attempt at a Solution

The first part is fine i get 1.4m/s2

then the second part to calculate tension im lost with what to do:

m1g-T=m1a

T-fk=m2a

where m1= 5kg

m2= 2kg

the answer is supposed to be 17N but when i solve for T i dont get anywhere near that...

thanks