(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An airplane is flying in a horizontal circle at a speed of 420 km/h. If the wings of the plane are tilted 35° to the horizontal, what is the radius of the circle in which the plane is flying? Assume that the required force is provided entirely by an aerodynamic lift that is perpendicular to the wing surface.

2. Relevant equations

a=v^2/r

Fc = Fnsin35°

3. The attempt at a solution

So first i looked at what was given:

V= 420 km/h = 116.67 m/s

r= ?

Since i know that the plane wings are tilted 35° to the horizontal, i broke the Fn into two parts the Fn pointing towards the centre of the circle being Fnsin35°

So:

Fc= Fnsin35°

ma=mgsin35°

a=gsin35°

(v^2/r) = gsin35°

(116.67m/s^2)^2/(9.8m/s^2)(sin35°)=r

r=2421.59 m

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# Homework Help: Need Help- Centripetal plane problem

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