1. The problem statement, all variables and given/known data You need to derive the general maximum height equation for projectile motion. This equation allows you to calculate the maximum height a projectile reaches or could reach during its motion. Like other such equations we derived in this unit, this one is also very short and simple. In this particular equation max height or YMAX can be defined or expressed in terms of Vm, g, θ, and one trig function. there is both a calculus and non-calculus derivation of this particular formula and both require careful and creative thinking. -The calculus method begins with using the trajectory equation. -The non-calculus method begins with setting up the charts. You may choose either method, but you must clearly show every step in the derivation process. Missing or unclear steps will result in a loss of points. Finally clearly write and circle your resulting formula as: YMAX= 2. Relevant equations Trajectory Equation: y=xtanθ-(gx2/2VL2cos2θ) 3. The attempt at a solution After some research I found that the equation should be: YMAX=(Vm2sin2θ/2g) I really don't even know where to start on this. He said that the non-calculus method is much easier. Any help would be greatly appreciated!