Need Help Designing Speaker Enclosure/Engineering

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    Designing Speaker
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Discussion Overview

The discussion revolves around the design of a closed baffle enclosure for a subwoofer, focusing on the calculations related to Thiele/Small parameters and the resulting volume of the enclosure. Participants explore the theoretical and practical aspects of speaker enclosure design, including compliance and volume calculations.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant presents their calculations for the acoustic driver compliance and box compliance, expressing confusion over the resulting volume being significantly higher than the manufacturer's recommendation.
  • Another participant calculates the equivalent compliance volume using the Thiele/Small parameters, arriving at approximately 49 liters, and offers to share their detailed calculation.
  • A participant questions the initial calculations, suggesting a potential error in the application of the equations and units, particularly regarding the use of Newtons in the calculations.
  • One participant performs a dimensional analysis to clarify the units involved in the calculations, concluding that the resulting units align with volume, while still expressing confusion about the role of Newtons.
  • Another participant shares a personal anecdote about their past experiences with learning and encourages the original poster to engage with the topic of speaker design.

Areas of Agreement / Disagreement

The discussion contains multiple competing views regarding the calculations and interpretations of the Thiele/Small parameters, with no consensus reached on the correct approach or resolution of the initial confusion.

Contextual Notes

Participants express uncertainty regarding the application of units and the calculations involved, highlighting potential missing assumptions and the complexity of the equations used.

Chris Larabee
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Hello all, first post here to physics forums and I have a lot to learn. I will be attending a northern Ontario university for Mechanical Engineering in fall so hopefully this relationship proves fruitful.

Here is my problem, I bought a new stereo for my jeep.. and I am having trouble designing a closed baffle enclosure for my 10.1'' subwoofer.

Here is where I am and how I got there, and why I am having trouble...

Given:
Fs = resonant frequency = 33.5 Hz
Cms = mechanical compliance = 0.0002m/N (metres / Newton)
Sd = effective area of cone = 0.0415m^2 (metres squared)

Unknown:

Cas = Acoustic Driver Compliance Cas=Cms*Sd^2
Cab = Acoustic Box Compliance Cab=Cas *R\
R= driver to box compliance ratio
R = 2

So: Cas = 0.0002m*(0.0415m^2)^2
=0.0002m/N*(0.00172225m^4)
Cas = 3.4 * 10 ^-7 m^5/N

Therefore Cab = 3.4 * 10 ^-7 m^5/N divided by two
= 1.72 x 10^-7m5/N

Now Volume of the Box Vb = Cab *Gamma Constant (Lets assume it is 5.77)
Vb = 1.72 x 10^-7 m^5 /N * 5,77
Vb = approx .99 x 10^-7m5/N

^^^^NOW HERE IS MY ISSUE^^^^

How the hell am I coming up with such a wrong answer, surly area is not expressed in terms of M^5/Newton and why is my volume so high? The Manufacturer recommends an enclosure from 0.08 m^2

please HELP, I will greatly appreciate it and contribute as much as I can to this forum :)

Also I am fresh out of high school took a year off, and its been 2 years since high level Math or Physics courses so please excuse me if the mistake I am making is pity.
 
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Hi Chris, and welcome to PF!
I checked the Thiele/Small parameters page on Wikipedia to look at the equation (which I did not know by heart), and my quick calculation with your numbers yielded an equivalent compliance volume that is 49 liter. I will post my calculation here in a while...

EDIT:
According to wiki, the equation is

Vas = ρ * c2 * Sd2 * Cms

and with your values above, this yields

Vas = 1.184 * 346.12 * 0.04152 * 0.0002 m3 ≈ 0.048852 m3 ≈ 49 liters.
 
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DennisN said:
Hi Chris, and welcome to PF!
I checked the Thiele/Small parameters page on Wikipedia to look at the equation (which I did not know by heart), and my quick calculation with your numbers yielded an equivalent compliance volume that is 49 liter. I will post my calculation here in a while...

EDIT:
According to wiki, the equation is

Vas = ρ * c2 * Sd2 * Cms

and with your values above, this yields

Vas = 1.184 * 346.12 * 0.04152 * 0.0002 m3 ≈ 0.048852 m3 ≈ 49 liters.
Thank you so much! If you could post your solution I would greatly appreciate it, I know there are other ways but I found the thiele parameters easy.. I'm sure that won't be the case for my mid frequency and tweeter drivers.
 
DennisN said:
Hi Chris, and welcome to PF!
I checked the Thiele/Small parameters page on Wikipedia to look at the equation (which I did not know by heart), and my quick calculation with your numbers yielded an equivalent compliance volume that is 49 liter. I will post my calculation here in a while...

EDIT:
According to wiki, the equation is

Vas = ρ * c2 * Sd2 * Cms

and with your values above, this yields

Vas = 1.184 * 346.12 * 0.04152 * 0.0002 m3 ≈ 0.048852 m3 ≈ 49 liters.
I noticed something in your calculations , shouldn't it be p * c^2 * (0.0415m^2)^2 * 0.0002m/N? Which leaves me in the same confused state as to what to do with Newtons
 
Chris Larabee said:
I noticed something in your calculations , shouldn't it be p * c^2 * (0.0415m^2)^2 * 0.0002m/N? Which leaves me in the same confused state as to what to do with Newtons

Maybe, just maybe, if we resolve everything to mass, length and time:

Newton is force which = ma so it could have units mass X length/time^2

so
Vas = ρ * c2 * Sd2 * Cmsrho would be mass/length^3
c^2 would be length^2/time^2
Sd^2 would be length^4
Cms in meters per Newton would be length/(mass X length/time^2) equals time^2/mass

so i get for units of Vas

[mass/length^3] X [length^2/time^2 ] X[length^4] X [ time^2/mass]

which has for numerator = mass X length^2 X length^4 X time^2
and has for denominator = length^3 X time^2 X 1 X mass

so mass cancels
time^2 cancels
all that's left is length^3 which is volume.

Chris Larabee said:
Which leaves me in the same confused state as to what to do with Newtons

use 'em to get rid of that pesky velocity and mass

hope above helps

old jim
 
jim hardy said:
Maybe, just maybe, if we resolve everything to mass, length and time:

Newton is force which = ma so it could have units mass X length/time^2

so
Vas = ρ * c2 * Sd2 * Cmsrho would be mass/length^3
c^2 would be length^2/time^2
Sd^2 would be length^4
Cms in meters per Newton would be length/(mass X length/time^2) equals time^2/mass

so i get for units of Vas

[mass/length^3] X [length^2/time^2 ] X[length^4] X [ time^2/mass]

which has for numerator = mass X length^2 X length^4 X time^2
and has for denominator = length^3 X time^2 X 1 X mass

so mass cancels
time^2 cancels
all that's left is length^3 which is volume.
use 'em to get rid of that pesky velocity and mass

hope above helps

old jim
Thank you sir, I had forgotten all about dimensional analysis. I was a bad student in grade 12, often stoned for the majority of physics so I don't recall much. I did much better in grade 11, and since have learned my lesson that smoking everyday is something my brain can no longer do if I wish to keep what intelligence I have left, let that be a lesson to some.

Thank you
 
I sacrificed quite a few brain cells to beer and won't cast stones.

Glad to see you digging into speakers, they're really interesting.

Have fun
 

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