Need help finding derivative/related rates

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physics=world
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1. Assume that x and y are both differentiable functions of t and find the required values of (dy/dt) and (dx/dt).

Equation ---> xy = 4

find (dy/dt) when x = 8

Given (dx/dt) = 10




Homework Equations


i tried to find the derivative of xy = 4

The Attempt at a Solution



x(dy/dt) + y(dx/dt) = 0

and then i just plugged in the values but that gave me -(10y/8)

and the answers is -(5/8)
 
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And what is y when xy=4 and x=8?
 
clamtrox said:
And what is y when xy=4 and x=8?

what do you mean? :confused:
 
physics=world said:
what do you mean? :confused:

Ohh. nvm i got it. thanks!
but may i ask why would i need to find for y?
 
physics=world said:
Ohh. nvm i got it. thanks!
but may i ask why would i need to find for y?

You know the value of y, so why would you leave it into the form you gave when you can equally well just give a number?
 
In this problem they're asking for the value of dy/dy at the moment when x = 8 and dx/dt = 10. With this information you can solve for y in the equation xy = 4, and evaluate dy/dt.