Need Help finding radius of ball using bouyancy

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Roger Wilco
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Homework Statement


An iron ball is suspended by a thread of negligible mass from an upright cylinder that floats partially submerged in water. The cylinder has a height of 6.00cm, a face area A=12.0 cm^2 on the top and bottom, and a density [tex]\rho_c=.300\frac{g}{cm^3}[/tex], and 2.00 cm of its height is above the water. What is the radius of the ball?

Homework Equations

[tex]\sum F=0[/tex] [tex]F_b=\rho*V*g[/tex]
Using Newton's Second and Archimedes' Principle I have used the following method. My concern comes at the point that I get the expression (V'-V)<-- this will yeild a NEGATIVE quantity and r cannot = negative. My problem is that the V'=volume of water displaced and V= volume of the cylinder. I think I need to assume that the CYLINDER IS HOLLOW in order to get a positive quantity. But whay is the volume of a hollow cylinder if I am not given an inner and outer radius??

The Attempt at a Solution



Subscript c is cylinder, b is the ball, and V' is the portion of the cylinder under water.

[tex]\sum F=0[/tex]

[tex]\Rightarrow W_c+W_b-F_{buoyant}=0[/tex]

[tex]\Rightarrow m_cg+m_bg-\rho_cV_c'g=0[/tex]

[tex]\Rightarrow \rho_cV_c+\rho_bV_b=\rho_cV_c'[/tex]

[tex]\Rightarrow V_b=\frac{\rho_c(V_c'-V_c)}{\rho_b}[/tex]

I don't find it necessary to move any further than this last step as finding the r is easy enough from there. However it is in this last step that you can see that if I use
V=height*cross-sectional area...I will get a negative number for V'-V.

What should I be using for V? Shoud it be zero? I think that is a bold assumption, or is it?

Thank you,
RW

Edit: After looking at my diagram, I have encountered another problem: Do I need to consider the buoyant force on the ball, too?

I do not not see why I wouldn't.

Okay. I also noticed that for F_bouyant I should have used rho_water NOT of the cylinder.

Guess I need to re-work this. :( So I guess in re-working this my question is still: do I need to consider the buoyant force on the ball, too?
 
Last edited:
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I think the problem is that you're multiplying V'c by the density of the cylinder and not the density of water which is what you need to do for the buoyant force.
 
Kurdt said:
I think the problem is that you're multiplying V'c by the density of the cylinder and not the density of water which is what you need to do for the buoyant force.

Yeah Kurdt, I just caught that. But tell me, should I be taking into account the buoyant Force of the ball?

See "Edits" in post #1.
 
Roger Wilco said:
Yeah Kurdt, I just caught that. But tell me, should I be taking into account the buoyant Force of the ball?

See "Edits" in post #1.

Thats a good thought, and yes I would do that. Its not that much harder.