Ʃ1. The problem statement, all variables and given/known data Determine the radius of convergence and the interval of convergence for the follwing function expanded about the point a=2. f(x)= ln(3-x) 2. Relevant equations ln(1-x) = Ʃ (x^n+1)/n+1 n=0 which has radius of convergence at |x|<1 3. The attempt at a solution I have figured it out ignoring the a=2. so, ln(3-x) = Ʃ (x^n+1)/(n+1)(3^n+1) comes out to |x/3|<1 interval of convergence (-3,3) radius of convergence = 3 but i feel like these arent the correct answers for what was asked, so my question is where does the a=2 come in place? any suggestions?