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## Homework Statement

Determine the radius of convergence and the interval of convergence for the follwing function expanded about the point a=2.

f(x)= ln(3-x)

## Homework Equations

ln(1-x) = Ʃ (x^n+1)/n+1 n=0 which has radius of convergence at |x|<1

## The Attempt at a Solution

I have figured it out ignoring the a=2.

so, ln(3-x) = Ʃ (x^n+1)/(n+1)(3^n+1) comes out to |x/3|<1

interval of convergence (-3,3) radius of convergence = 3

but i feel like these arent the correct answers for what was asked, so my question is where does the a=2 come in place?

any suggestions?